C++ Variable argument functions are useful wherever we are not sure about the number of parameters to be passed. Not all the compilers have the ability to decipher variable arguments. But C++ compiler has the capability to decrypt a variable argument function and provide the parameter values inside the function.

   The first confusion that would arise when using a variable argument is to identify the type of the variable. The data type of the variable should be known prior to using it in a variable argument function. The algorithm/code inside the function should be able to manipulate the data properly.

   The argument values can be retrieved by using the va_arg, va_start and va_end macros. These macros assume that the function will be called with a fixed number of required parameters and variable number of optional parameters.

   The following sample program uses a function Add with variable arguments and returns the value of the added items.

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#include <stdio.h>
#include <stdargs.h>

int Add(int a,int b,...)
{

//This one handles 4 arguments in total.
int l_ParamVal=0;
int total=0;
int i;

//Declare a va_list macro and initialize it with va_start
va_list l_Arg;
va_start(l_Arg,a);

//The required parameters can also be accessed directly
l_ParamVal = a;
printf("%d\n",l_ParamVal);
if(l_ParamVal != -1)
total = total +l_ParamVal;

l_ParamVal = va_arg(l_Arg,int);
printf("%d\n",l_ParamVal);
if(l_ParamVal != -1)
total = total +l_ParamVal;

l_ParamVal = va_arg(l_Arg,int);
printf("%d\n",l_ParamVal);
if(l_ParamVal != -1)
total = total +l_ParamVal;

l_ParamVal = va_arg(l_Arg,int);
printf("%d\n",l_ParamVal);
if(l_ParamVal != -1)
total = total +l_ParamVal;

va_end(l_Arg);

return total;

}

void main()
{

printf("Total of C++ Variable Arguments: %d\n",Add(2,3,4));

}

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   The above sample takes some integer parameters and returns their added result. This function can handle up to 4 parameters.